Question : What is the value of a2 + b2 + c2 – 2ab – 2bc + 2ca?
Option 1: (2a + b + c)2
Option 2: (a – b + c)2
Option 3: (a – b – 2c)2
Option 4: (a + 2b – c)2
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: (a – b + c) 2
Solution : We know that (x + y + z) 2 = (x 2 + y 2 + z 2 + 2xy + 2yz + 2zx) Comparing the RHS of the above formula with the given expression, we get: x = a, y = –b, and z = c So, a 2 + b 2 + c 2 – 2ab – 2bc + 2ca = (a – b + c) 2 Hence, the correct answer is (a – b + c) 2 .
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : If $\frac{a}{1-2a}+\frac{b}{1-2b}+\frac{c}{1-2c}=\frac{1}{2}$, then the value of $\frac{1}{1-2a}+\frac{1}{1-2b}+\frac{1}{1-2c}$ is:
Question : What is the value of (a + b)3 – a3 + b3?
Question : If (a – b) = 1, what is the value of (a3 – b3)?
Question : If a + b + c = 1, ab + bc + ca = –22 and abc = –40, then what is the value of a3 + b3 + c3 ?
Question : The value of $x$ which satisfies the equation $\frac{x \:+\: a^2 \:+\: 2c^2}{b \:+\: c} + \frac{x \:+\: b^2 \:+\: 2a^2}{c+a} + \frac{x \:+\: c^2 \:+\: 2b^2}{a \:+\: b} = 0$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile