Question : What is the value of $42 \div[18-\{6+(3$ of $4-4-2$ of 5$)\}] ?$
Option 1: 5
Option 2: 6
Option 3: 2
Option 4: 3
Answer (1)
23rd Jan, 2024
Correct Answer: 3
Solution :
Given: $42 \div[18-\{6+(3$ of $4-4-2$ of 5$)\}]$
= $42 \div[18-\{6+(12-4-10)\}]$
= $42 \div[18-\{6-2\}]$
= $42 \div[18-4]$
= $\frac{42}{14}$
= 3
Hence, the correct answer is 3.
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