Question : What is the value of $42 \div[18-\{6+(3$ of $4-4-2$ of 5$)\}] ?$
Option 1: 5
Option 2: 6
Option 3: 2
Option 4: 3
New: SSC MTS Tier 1 Answer key 2024 out
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 3
Solution : Given: $42 \div[18-\{6+(3$ of $4-4-2$ of 5$)\}]$ = $42 \div[18-\{6+(12-4-10)\}]$ = $42 \div[18-\{6-2\}]$ = $42 \div[18-4]$ = $\frac{42}{14}$ = 3 Hence, the correct answer is 3.
Answer Key | Cutoff | Selection Process | Preparation Tips | Eligibility | Application | Exam Pattern
Question : The value of $[50-6(6+1)] \div 8+18$ is:
Question : What is the value of $\frac{12 \times 4 \div 3 \text { of } 16+24-5}{46 \div 23 \times 2}$?
Question : What is the value of $\left[\frac{1}{5}+\left\{\frac{1}{6}\right.\right.$ of $\left.\left.\left(\frac{42}{35} \div \frac{6}{25}\right)–\left(\frac{2}{7} \times \frac{6}{5} \div \frac{18}{42}\right)\right\}+\frac{19}{30}\right]$?
Question : If $\frac{2 x+3}{18 \div 3 \times 4+2}=\frac{12 \times 3+5}{2 \times 4 \div 2}$, then what is the value of $x$?
Question : What is the value of $\frac{99 \div 33+44 \div 11 \text { of } 4}{24 \div 12–4+3}$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile