Question : What is the value of $42 \div[18-\{6+(3$ of $4-4-2$ of 5$)\}] ?$
Option 1: 5
Option 2: 6
Option 3: 2
Option 4: 3
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Correct Answer: 3
Solution : Given: $42 \div[18-\{6+(3$ of $4-4-2$ of 5$)\}]$ = $42 \div[18-\{6+(12-4-10)\}]$ = $42 \div[18-\{6-2\}]$ = $42 \div[18-4]$ = $\frac{42}{14}$ = 3 Hence, the correct answer is 3.
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