Question : What is the value of $\frac{1}{2}$ of $\frac{16}{5}+\frac{1}{8}$ of $\frac{24}{9} \times \frac{18}{12}-\frac{5}{8}$?
Option 1: $\frac{51}{40}$
Option 2: $\frac{68}{39}$
Option 3: $\frac{59}{40}$
Option 4: $\frac{61}{50}$
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Correct Answer: $\frac{59}{40}$
Solution : Given: $\frac{1}{2}$ of $\frac{16}{5}+\frac{1}{8}$ of $\frac{24}{9} \times \frac{18}{12}-\frac{5}{8}$ = $\frac{8}{5}+\frac{1}{3}\times \frac{3}{2}-\frac{5}{8}$ = $\frac{8}{5}+\frac{1}{2}-\frac{5}{8}$ = $\frac{8}{5}+\frac{4-5}{8}$ = $\frac{8}{5}-\frac{1}{8}$ = $\frac{64-5}{40}$ = $\frac{59}{40}$ Hence, the correct answer is $\frac{59}{40}$.
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