Question : What is the value of the given expression?
$\frac{4^{a + 4}- 5 \times 4^{a + 2}}{15 \times 4^a - 2^2 \times 4^a}$
Option 1: 16
Option 2: 64
Option 3: 20
Option 4: 24
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Answer (1)
20th Jan, 2024
Correct Answer: 16
Solution :
$\frac{4^{a+ 2}(4^{2} - 5 \times 1)}{4^{a}(15 - 4)}$
$=\frac{4^{a + 2}(11)}{4^{a}(11)}$
$=\frac{4^{a}\times4^{2}(11)}{4^{a}(11)}$
$=4^2$
$=16$
Hence, the correct answer is 16.
Comments (0)
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Thank You!
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Mains Exam
Admit Card Date:
23 Nov, 2024
- 30 Nov, 2024
Application Date:
2 Dec, 2024
- 31 Dec, 2024
Application Date:
22 Nov, 2024
- 12 Dec, 2024
Admit Card Date:
20 Nov, 2024
- 15 Dec, 2024
