Question : What is the value of $64x^{3} + 36x^{2}y + 24xy^{2} + 2y^{3}$, when $x = 3$ and $y = -4?$
Option 1: $304$
Option 2: $1456$
Option 3: $1584$
Option 4: $432$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $1456$
Solution : Given: $x = 3, y = -4$ So, the value of $64x^{3} + 36x^{2}y + 24xy^{2} + 2y^{3}$ $=x^{2}(64x + 36y) + y^{2}(24x + 2y)$ $=3^{2}[(64 × 3) + (36 × -4)] + (-4)^{2}[(24 × 3) + (2 × -4)]$ $=9 × [192 -144] + 16 × [72 -8]$ $=(9 × 48) + (16 × 64)$ $=432 + 1024$ $=1456$ Hence, the correct answer is $1456$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : The simplified form of $(x+2y)^3 + (x-2y)^3$ is:
Question : If $x^2-xy+y^2=2$ and $x^4+x^2y^2+y^4=6$, then the value of $(x^2+xy+y^2)$ is:
Question : What is the value of $64 x^3+38 x^2 y+20 x y^2+y^3$, when $x=3$ and $y=-4$?
Question : If $(x+y)^2=xy+1$ and $x^3-y^3=1$, what is the value of $(x-y)$?
Question : What is the solution of the following equations? 2x + 3y = 12 and 3x – 2y = 5
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile