what is the work function of the metal if the light of wavelength 4000 A generates photoelectrons of velocity 6 x 10^5
Answer (1)
10th Mar, 2020
Hi Saksham,
We know that kinetic energy is 1/2 mv^2
According to the question mass is equals to 9 * 10^-31 and the velocity is 6*10^5 .
Putting the values of mass and velocity in the formula of kinetic energy we will get 162*10^-21 i.e. approximately 1 ev.
Now the energy of photon E is 12400/4000= 3.1 eV.
And E= kinetic energy+ fi
3.1 = 1+ fi
Fi = 2.1 eV
I hope your question has been answered properly.
All the best for your future!
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