what percentage of marks in jee advanced exam is necessary to get computer science in IIT Roorkee?

Hi Sourish,

The prediction of exact percentile or rank or marks required in JEE Advanced to get admission in CSE brach in IIT Roorkee is quite difficult.

The cutoffs are decided on the following criteria:-

• Previous years’ cutoff trends

• Number of seats in the courses offered by the institute

• Number of candidates who appeared for JEE Advanced 2020

• Difficulty level of the entrance examination

These are the cutoffs@2019 of CSE Branch of IIT Roorkee:-

• General - AIR 412
• OBC - AIR 195
• EWS - AIR 33
• SC- AIR 102
• ST - AIR 68

Cutoffs@2018 :-

• General - AIR 416
• OBC NCL - AIR 225
• SC- AIR 108
• ST - AIR 82

From these previous year cutoffs you will get an idea of the rank required to get CSE Branch in IIT Roorkee.

You may refer to the source article for more information about JEE Advanced Cutoff for IIT Roorkee.

Your one-stop B.Tech Counselling package with Full-Length JEE Main Mock Tests, 15+ College Predictors, a printed Almanac with 1000+ FAQs on Admissions & more

B. Tech Companion

If you require to know colleges for which you are eligible then you should go to the link mentioned below.

Link - JEE Main College Predictor

I hope this information helps you.

Good Luck!