what percentile do i need to get admission in NIT patna CSE or ECE with female obc quota and home state quota?

Hello Aspirant,

As we go through the latest cut-off of 2020 then it shows that the closing OBC rank was 10465 for CS Engineering and 12423 for ECE branch in NIT Patna under Home state quota for OBC category female.

Now to secure such rank you should have your JEE-Main  score at least 110+ marks out of 300 and percentile against this should be around 96.5+.

You can check out the latest cut-offs from the link given below :-

https://josaa.nic.in/Result/Result/currentorcr.aspx

You can check out marks Vs ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

Or

You can also use JEE-Main Rank Predictor to predict your rank :-

JEE Main Rank Predictor 2021 - Predict your JEE Main 2021 Rank, JEE Main Percentile Calculator

JEE Main Rank Predictor - Know your expected IIT JEE Main 2021 Rank by using Careers360 JEE Main rank predictor tool based on JEE Mains scor ...

Note that the above prediction is made on the basis of latest cut-offs available on official website of JOSAA or CSAB and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.

To have a list of all those colleges which you can get based upon your score, category, and state you can use JEE-Main College Predictor :-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

As you are preparing for JEE-Main then I would recommend you to check the resources made by our experts to help aspirants like you in the best and smart preparation of JEE-Main :-

https://learn.careers360.com/jee-main-coaching/?utm_source=%20QnA

I hope this information helps you.

Good Luck!!