What percentile does I need to get 2000 rank in mht cet 2019
Hi Suyash,
The total number of candidates from the PCM background in MHT CET 2019 was 1,20,000.
And, the total number of candidates from the PCMB background in MHT CET 2019 was 1,70,000.
Therefore, the total number of candidates for Engineering was 2,76,166.
For example, if someone scores 92 percentile in MHT CET 2019, then his/her rank will be-
2,76,166 * 0.08 = 22,093
If you want to secure a rank around 2,000 , you need a 99.28 percentile-
2,76,166 * 0.0072 = 1,988
Hope this helps you.
All the best!!!!
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