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hello aspirant,
It’s difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula
your percentile is to understand the number of student who are ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100
It’s difficult to tell exact qualifying marks for jee advanced eligibility but if you are getting more than 85 percentile score then you have decent chances to qualify for jee advanced
B.Tech/B.Arch Admissions OPEN
moreover the percentile of jee mains can be calculated by using the formula of the following.
total number of student below your score /total number of students who attended the exam X 100 gives your percentile. as per the last year result analysis your percentile score comes as 94-95 in between.
hope this helps..
all the best
You haven't mentioned your Category. Assuming your Category to be General, here you go:
After considering the Paper 1 inputs
Your Overall Percentile is: 94.47 - 94.67
Your General Rank is: 48980 - 59130
But if you belong to any other Category, please feel free to use our JEE rank predictor:
JEE Main Rank Predictor - Know your expected IIT JEE Main 2020 Rank by ...
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