Hello there

To get CSE branch in IIT Kharagpur or IIT Roorkee you need to score a rank below 400.Because both of these IITs are among the top IITs and computer science engineering is most popular B.Tech branch.



Hope I am clear

Hi aspirant,

CSE is one of the most popular engineering branch in India and both IIT Roorkee and IIT Kharagpur are the best engineering institutes. Hence, they have a high cut-off. As of 2018, the cutoff for CSE for OBC-NCL at IIT Roorkee WAS 225 and at IIT Kharagpur was 137. This year's cut-off are also expected to be similar. So your category rank should be somewhere between 100-150.

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