33 Views

Question : What will be the area of a plot of quadrilateral shape, one of whose diagonals is 20 m and lengths of the perpendiculars from the opposite vertices on it are 12 m and 18 m, respectively?

Option 1: 400 m2

Option 2: 250 m2

Option 3: 200 m2

Option 4: 300 m2


Team Careers360 13th Jan, 2024
Answer (1)
Team Careers360 17th Jan, 2024

Correct Answer: 300 m 2


Solution :
Given: The diagonals are 20 m and the lengths of the perpendiculars from the opposite vertices on it are 12 m and 18 m, respectively.
Use the formula, $\text{Area of the triangle}=\frac{1}{2}\times \text{Base}\times \text{Height}$.
The area of the $\triangle ABC=\frac{1}{2}\times \text{AC}\times \text{BO}=\frac{1}{2} \times 20\times 12=120$ m 2 .
The area of the $\triangle ADC=\frac{1}{2}\times \text{AC}\times \text{DP}=\frac{1}{2}\times 20\times 18=180$ m 2 .
The area of a plot of quadrilateral shape = 180 + 120 = 300 m 2 ​​​​​
Hence, the correct answer is 300 m 2 .

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books