Hi

This is a bit difficult to predict the marks/percentile/rank required in JEE mains as closing rank keeps changing every year  depending upon various factors like  number of students that appeared in the exam, kind of marks obtained by them , toughness level of the jee main examination , number of seats available for the branch you want etc.

But yes,

When we go through previous year trend then ,

Under other state quota , closing rank for some of the nits for which closing rank goes low are listed below along with their closing rank in the 6th round of josaa counselling 2020 for obc category  :-

• NIT Mizoram ,civil engineering :-14730 obc rank

• Nit nagaland ,Electronics and Instrumentation Engineering (4 Years, Bachelor of Technology) :-  15340 obc rank

• National Institute of Technology AgartalaProduction Engineering (4 Years, Bachelor of Technology :- 15659  obc rank

• National Institute of Technology, Surat:-Chemistry (5 Years, Integrated Master of Science):-16453 obc rank

You can verify the above at

https://josaa.nic.in/Result/Result/currentorcr.aspx

So, to get a seat in NIT you should get at least around 15000 - 16000 OBC rank i. e around 94.5 - 95 percentile

This prediction of is on the basis of past year data but  cut off/closing rank for colleges keeps changing every year depending upon many factors like number of students that appeared in the examination, difficulty level of the JEE main question paper for different shifts etc

To get  a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To prepare well for jee main, visit

https://learn.careers360.com/knockout-jee-main

To help you further,

To give you an idea of qualifying cut off, JEE mains 2020  qualifying  CUT OFF percentile to be eligible for jee advanced is given below for different category

>>>> General :-     90.3765335

>>>> GEN-EWS :-  70.2435518

>>>> OBC-NCL :-  72.8887969

>>>> SC     :-           50.1760245

>>>> ST :-                39.0696101

>>>> PwD :-            0.0618524

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

Thankyou