What would be the cuttoff for jnec this year?
Following is the expected cut off for a general candidate :
CSE- 18969
Civil engineering -16721
Mechanical engineering- 21367
Chemical engineering -38955
Information technology -22738
Hope this may give you an idea ....
Good luck !!!!
Hi Stelujin,
Candidates seeking admission to Engineering and Technology courses are required to appear for JEE Main (Paper 1) conducted by Central Board of Secondary Education (CBSE). Candidate should obtain Positive Composite Score, positive composite score is obtained after adding 50% of JEE Mains Paper 1 and 50% of normalized standard XII (Board or Equivalent examination) marks is Physics, Chemistry and Mathematics (PCM).Amd may be the cutoff for this year will be around 48.
Feel free to ask if you have any more queries.
Thank You