What's the cutoff mark for cs in new 2

The cutoff for Computer Science Engineering (CSE) in newer IITs typically ranges from 99.2 to 99.9 percentile, depending on the institute. For JEE Main 2024, a score of around 250 or higher should help you secure a percentile above 99.5, which is competitive for newer IITs. Keep an eye on official sources like JoSAA for the latest cutoff details and practice previous year’s papers to improve your chances.

Hello,

The cutoff marks for Computer Science (CS) in the second round of admissions vary across institutions. Here are some examples:

• Hansraj College, Delhi University: For B.Sc. (Hons.) Computer Science, the expected CUET UG 2024 cutoff is around 755 for the general category.
• Sister Nivedita University, Kolkata: In 2024, the WBJEE cutoff for B.Tech in Computer Science & Engineering ranged from an opening rank of 10,288 to a closing rank of 110,967.
• IIT Kanpur: For the SC category, the JoSAA Round 2 cutoff in 2024 for Computer Science and Engineering had an opening rank of 55 and a closing rank of 96.

Please note that cutoff marks are subject to change each year based on factors like the number of applicants, difficulty level of entrance exams, and seat availablity.

If you want information regarding a specific university admission pr entrance exam, please ask your query with relevant information like University name and examination name.

Hope it helps !

Hello,

The cutoff marks for admission into Computer Science and Engineering (CSE) programs differ widely depending on the institution and entrance exam. For example, in 2023, the closing rank for CSE at top IITs like IIT Bombay was 67, whereas, for newer IITs like IIT Dharwad, it went up to 5,978. Similarly, at NITs, the cutoff for CSE also varied, with institutes like NIT Calicut having relatively competitive closing ranks. These cutoff ranks are influenced by factors like the number of applicants, seat availability, and the difficulty level of the entrance exam.