Question : When 2388, 4309, and 8151 are divided by a certain 3-digit number, the remainder in each case is the same. The remainder is:
Option 1: 23
Option 2: 19
Option 3: 39
Option 4: 15
Correct Answer: 15
Solution :
According to the question,
4309 – 2388 = 1921
8151 – 4309 = 3842
8151 – 2388 = 5763
HCF of 1921, 3842 and 5763 = 1921
1921 = 17 × 113
Thus, the three-digit number is 113.
When 2388, 4309, and 8151 are divided by 113, the remainder is 15 in each case.
Hence, the correct answer is 15.
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