Question : When a certain number is divided by 65, the remainder is 56. When the same number is divided by 13, the remainder is $x$. What is the value of $\sqrt{5x-2}$?
Option 1: $2 \sqrt{7}$
Option 2: $\sqrt{13}$
Option 3: $2 \sqrt{2}$
Option 4: $3 \sqrt{2}$
Correct Answer: $3 \sqrt{2}$
Solution : Given: When a certain number is divided by 65, the remainder is 56. When the same number is divided by 13, the remainder is $x$. Since 65 is divisible by 13, the required remainder is the remainder when 56 is divided by 13. Divide 56 by 13, we get the remainder $x=4$. The value of $\sqrt{5x-2}$ $=\sqrt{5\times 4-2}$ $=\sqrt{20-2}=\sqrt{18}=3 \sqrt{2}$ Hence, the correct answer is $3 \sqrt{2}$.
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Question : A number, when divided by 729, gives a remainder of 56. What will we get as a remainder if the same number is divided by 27?
Option 1: 4
Option 2: 2
Option 3: 0
Option 4: 1
Question : If $x^2-\sqrt{7} x+1=0$, then $\left(x^3+x^{-3}\right)=?$
Option 1: $4 \sqrt{7}$
Option 2: $3 \sqrt{7}$
Option 3: $10 \sqrt{7}$
Option 4: $7 \sqrt{7}$
Question : When a number is successively divided by 3, 4, and 7, the remainder obtained is 2, 3, and 5 respectively. What will be the remainder when 42 divides the same number?
Option 1: 41
Option 2: 30
Option 3: 29
Option 4: 31
Question : When a number is successively divided by 3, 4 and 7, the remainder obtained are 2, 3 and 5, respectively. What will be the remainder when 84 divides the same number?
Option 1: 71
Option 3: 48
Option 4: 53
Question : If $x^2+\frac{1}{x^2}=\frac{7}{4}$ for $x>0$; then what is the value of $x+\frac{1}{x}$?
Option 1: $2$
Option 2: $\frac{\sqrt{15}}{2}$
Option 3: $\sqrt{5}$
Option 4: $\sqrt{3}$
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