9 Views

Question : When a certain number is divided by 65, the remainder is 56. When the same number is divided by 13, the remainder is $x$. What is the value of $\sqrt{5x-2}$?

Option 1: $2 \sqrt{7}$

Option 2: $\sqrt{13}$

Option 3: $2 \sqrt{2}$

Option 4: $3 \sqrt{2}$


Team Careers360 6th Jan, 2024
Answer (1)
Team Careers360 15th Jan, 2024

Correct Answer: $3 \sqrt{2}$


Solution : Given: When a certain number is divided by 65, the remainder is 56.
When the same number is divided by 13, the remainder is $x$.
Since 65 is divisible by 13, the required remainder is the remainder when 56 is divided by 13.
Divide 56 by 13, we get the remainder $x=4$.
The value of $\sqrt{5x-2}$
$=\sqrt{5\times 4-2}$
$=\sqrt{20-2}=\sqrt{18}=3 \sqrt{2}$
Hence, the correct answer is $3 \sqrt{2}$.

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books