When a certain photosensitive surface is illuminated with monochromatic light of frequency \nu , the stopping potential for the photo current is - \frac{V_{0}}{2} . When the surface is illuminated by monochromatic light of frequency \frac{\nu}{2} , the stopping potential is - V_{0} . The threshold f
Answer (1)
15th Jan, 2020
h\nu = W + \dfrac{v_o}{2} ehν=W+2voe
\dfrac{h\nu}{2} = W + v_o e2hν=W+voe
on solving we get, W = 3/2 h \nuW=3/2hν
hv_o = 3/2 h \nuhvo=3/2hν
v_o = 3/2 vvo=3/2v
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