Hello aspirant,
To find the area of the cross-section of the wire, we can use the formula for Young's modulus:
Y = (F * L) / (A * ΔL)

where:

• Y is Young's modulus
• F is the force applied (weight of the load)
• L is the original length of the wire
• A is the cross-sectional area of the wire
• ΔL is the change in length of the wire
  
  

We can rearrange the formula to solve for A:
A = (F * L) / (Y * ΔL)

Given:

• F = 10 kg * 9.81 m/s² = 98.1 N
• L = 5 m
• Y = 9.8 * 10^10 N/m²

• ΔL = 5 mm = 0.005 m
  
  

• 
  

  Substituting the values into the formula:

  A = (98.1 N * 5 m) / (9.8 * 10^10 N/m² * 0.005 m)
  

  Calculating:

  A ≈ 1.00 * 10^-6 m²
  

  Therefore, the area of the cross-section of the wire is approximately 1.00 * 10^- 6 square meters . (https://unacademy.com/content/cbse-class-11/study-material/physics/youngs

  I hope this helps you.