Question : When the number is divided by 15, 20, and 35 each time the remainder is 8. What is the smallest number?
Option 1: 428
Option 2: 427
Option 3: 328
Option 4: 338
Answer (1)
21st Jan, 2024
Correct Answer: 428
Solution :
15 = 3 × 5
20 = 2 × 2 × 5
35 = 5 × 7
LCM of 15, 20 and 35 = 7 × 5 × 3 × 2 × 2 = 420
Adding the remainder 8 to 420, we get 428, which, when divided by 15, 20, 35, leaves the remainder 8 in each case.
Hence, the correct answer is 428.
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