Question : Which of the following is the smallest ratio?
$\frac{5}{6}, \frac{7}{9}, \frac{11}{12}, \frac{13}{18}$

Option 1: $\frac{7}{9}$

Option 2: $\frac{13}{18}$

Option 3: $\frac{5}{6}$

Option 4: $\frac{11}{12}$

Question : Which one is the largest among the fractions?
$\frac{5}{113},\frac{7}{120},\frac{13}{145}$ and $\frac{17}{160}$

Option 1: $\frac{5}{113}$

Option 2: $\frac{7}{120}$

Option 3: $\frac{13}{145}$

Option 4: $\frac{17}{160}$

Question : The sum of three fractions is $2\frac{11}{24}$. On dividing the largest faction by the smallest fraction, $\frac{7}{6}$ is obtained which is $\frac{1}{3}$ greater than the middle fraction. The smallest fraction is:

Option 1: $\frac{5}{8}$

Option 2: $\frac{3}{4}$

Option 3: $\frac{5}{6}$

Option 4: $\frac{3}{7}$

Question : Let $x=\frac{5 \frac{3}{4}-\frac{3}{7} \times 15 \frac{3}{4}+2 \frac{2}{35} \div 1 \frac{11}{25}}{\frac{3}{4} \div 5 \frac{1}{4}+5 \frac{3}{5} \div 3 \frac{4}{15}}$. When $y$ is added to $x$, the result is $\frac{7}{13}$. What is the value of $y$?

Option 1: $\frac{1}{13}$

Option 2: $\frac{9}{13}$

Option 3: $\frac{2}{13}$

Option 4: $\frac{4}{13}$

Question : Choose the option in which the numbers are in the correct ascending order.

Option 1: $\frac{4}{5}, \frac{2}{3}, \frac{1}{11}$ and $\frac{2}{9}$

Option 2: $\frac{1}{11}, \frac{2}{9}, \frac{2}{3}$ and $\frac{4}{5}$

Option 3: $\frac{2}{9}, \frac{1}{11}, \frac{4}{5}$ and $\frac{2}{3}$

Option 4: $\frac{2}{3}, \frac{4}{5}, \frac{1}{11}$ and $\frac{2}{9}$