which iit i will get csc branch if I got 130 marks in jee advanced and I am belongs to obv ncl category
New: Direct link to apply for JEE Main 2025 registration for session 1
Also Check: Crack JEE Main 2025 - Join Our Free Crash Course Now!
JEE Main 2025: Sample Papers | Syllabus | Mock Tests | PYQs | Video Lectures
JEE Main 2025: Preparation Guide | High Scoring Topics | Study Plan 100 Days
Hi Dileep,
Congratulations on making into JEE Advance.
I am sorry to say that, though the exam has not been conducted yet, it will be difficult to say anything about the cut-off, colleges, and branches. Based on the difficulty level, it changes every year.
But to answer your curiosity, based on previous years' trend, by scoring 130 marks in JEE Advance, your rank can hover between 4500 to 10000.
Therefore, for better prediction on JEE Advance rank, I will suggest you visit this link - https://engineering.careers360.com/articles/jee-advanced-rank-predictor
For precise information on IIT College and branches, you can get based on your marks, visit this link - https://engineering.careers360.com/jee-advanced-college-predictor
All the best for your exam.
If you score 130 in JEE Advanced, your rank will be approximately 10000. So, with this rank there is less chance of getting good IITs. You may get lower branches in some New IITs. Better not to think about marks and prepare well. You need to score at least 150 to get CSE in old IITs.
Hope you understand. All the best.
Related Questions
Know More about
Joint Entrance Examination (Main)
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates BrochureYour Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.
Joint Entrance Exam Advanced
Application | Eligibility | Exam Pattern | Admit Card | Preparation Tips | Answer Key | Result | Accepting Colleges
Get Updates BrochureYour Joint Entrance Exam Advanced brochure has been successfully mailed to your registered email id “”.