Which institute should i prefer nit surat ece/nit nagpur ece or indian institute of information technology pune (iiit pune) cse ????
Hello,
Between ECE in NIT Nagpur or NIT Surat and CSE in IIIT Pune. I'll recommend you to go for CSE Department in IIIT Pune since you'll have tremendous opportunities for placements during your final years. ECE department also has nice placement stats but CSE prevail over it.
The NIT tag does hold value but IIITs are no less and you'll surely be happy with your decision, but if you're passionate about ECE department then you should go for it. Now for ece department to choose between NIT Surat or NIT Nagpur I'll recommend you to go for NIT Surat since it's better in terms of infrastructure and location. Academics and placements are more or less same for both the institutes.
The choice is yours whether you wanna pursue ECE or CSE but you should choose wisely since it'll determine the next 4 important years of your life and you should pursue the field which you find the most interesting.
Hope this helps.
I think you should prefer NIT Surat ECE/NIT Nagpur ECE above IIIT Pune CSE. IIIT Pune, is still a new institute and loses out to the former 2 NITs on Infrastructure and Outlook. Of course, if you are so determined to study nothing but CSE ,you can of course opt for the latter option.
Classifying Further, I believe NIT Nagpur ECE, will be a better choice than NIT Surat ECE. Pune ,being an upcoming IT Hub of the Country and vicinity to Mumbai and Bengaluru will provide you with numerous opportunitues in context of training, internships and placement. Placements are never a concern when it comes to older NITs amd secondly the branch being ECE, you can be assured of excellent placements and packages touching 10 LPA and upwards on an average. However few Companies and MnCs like Intel, Facebook and Texas Instruments visit NIT Nagpur but not NIT Surat.
For more information and College Prediction do follow the link below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
