Question : Which is the largest six-digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainder 8, 11, 16, 20 and 26 respectively.
Option 1: 999956
Option 2: 999982
Option 3: 999960
Option 4: 999964
Correct Answer: 999956
Solution : LCM of 12, 15, 20, 24, 30 is 120 As we know, (12 – 8) = (15 – 11) = (20 – 16) = (24 – 20) = (30 – 26) = 4 As we know, The largest 6-digit number = 999999 ⇒ Number divisible by 120 = 999999 – 39 = 999960 $\therefore$ Required number = 999960 – 4 = 999956 Hence, the correct answer is 999956.
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