Question : Which is the smallest three-digit number which when increased by 5 becomes divisible by both 2 and 3?
Option 1: 102
Option 2: 105
Option 3: 103
Option 4: 108
Correct Answer: 103
Solution :
Consider the numbers,
102, 103, 105, and 108
⇒ For 102,
When increased by 5, the number becomes 107 which is not divisible by 2.
Now, The number = 103
When increased by 5, the number = 108
⇒ $\frac{108}{2}=54$ and $\frac{108}{3}=36$
Number = 105, when increased by 5, it becomes 110, which is not divisible by 3.
Number = 108, when increased by 5, it becomes 113, which is not divisible by 2.
Hence, the correct answer is 103.
Related Questions
Know More about
Staff Selection Commission Multi Tasking ...
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Get Updates Brochure
Your Staff Selection Commission Multi Tasking Staff Exam brochure has been successfully mailed to your registered email id “”.
