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Question : Which is the smallest three-digit number which when increased by 5 becomes divisible by both 2 and 3?

Option 1: 102

Option 2: 105

Option 3: 103

Option 4: 108


Team Careers360 20th Jan, 2024
Answer (1)
Team Careers360 25th Jan, 2024

Correct Answer: 103


Solution : Consider the numbers,
102, 103, 105, and 108
⇒ For 102,
When increased by 5, the number becomes 107 which is not divisible by 2.
Now, The number = 103
When increased by 5, the number = 108
⇒ $\frac{108}{2}=54$ and $\frac{108}{3}=36$
Number = 105, when increased by 5, it becomes 110, which is not divisible by 3.
Number = 108, when increased by 5, it becomes 113, which is not divisible by 2.
Hence, the correct answer is 103.

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