which nit will get in cse branch when my ward secured 98.5 percentile in jeemain jan.2020. we are obc in bihar state.
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Hi dear,
You have scored 98.5 percentile in JEE main that means your rank should be around 13035. You can also calculate your rank
Rank=(100-your percentile)×869010÷100
However his final rank will depend on number of student appear in April month exam. He has a chance to get cse in NIT Patna and NIT Jamshedpur.
Hope it helps.
Dear aspirant,according to your percentile score in JEE MAIN examination your expected rank is about 13,035. With this rank you are expected to be in the top 1k or 2k rank in your respective category. Being the residents of Bihar you can easily expect CSE at NIT Patna as home state closing rank is 4531. Imvattaching a link where you can check cutoffs for CSE for NITs for OBC category.
Link-https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches.
Thank you hope this helps you!
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