Question : Which of the following expressions is equal to the expression $\frac{x^2-3 x+2}{x^2-4}$?
Option 1: $\frac{x+1}{x-2}$
Option 2: $\frac{x-1}{x+2}$
Option 3: $\frac{x+1}{x+2}$
Option 4: $\frac{x-1}{x-2}$
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Correct Answer: $\frac{x-1}{x+2}$
Solution :
$\frac{x^2-3 x+2}{x^2-4}$
= $\frac{(x-2)(x-1)}{(x-2)(x+2)}$
= $\frac{(x-1)}{(x+2)}$
Hence, the correct answer is $\frac{(x-1)}{(x+2)}$.
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