Hello Gaikwadomkar,

As we know to find maximum number of molecules  we have to divide the given mass by its molar mass to get moles, then multiply times 6.022×1023 molecules1 mol

Now to answer your question 1 mole of any element contain 6.023 x 1023 number of molecules.

1 g mole of N2 = 28 g N2 => 7 g N2 = 0.25 g mole N2

1 g mole of O2 = 32 g O2  => 16 g of O2 = 0.5 g mole O2

1 g mole of H2 = 2 g H2 => 2 g H2 = 1.0 g mole H2

1 g mole NO2 = 14 + 16 x 2 = 46 => 16 g of NO2 = 0.35 mole NO2

2 g H2 (1 g mole H2) contain maximum molecules.

hope  this will help you a lot.

thank you.

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Hello

The correct option is b) 2g H2

EXPLANATION

we know that,

No. of moles is given by

= Molecular weight (M)/ given Weight (W)

Therefore,

(a) No. of moles in a option =7 /28= 0.25 moles

(b) No. of moles in b option i.e H2=2/2 = 1 mole

(c) No. of moles in c option =16 /46= 0.347 moles

(d) No. of moles in D option =16 /32= 0.5 moles

Now as H2 has maximum no. of moles, thus it has maximum no. of molecules

Thank you