Correct Answer: $\frac{3}{5}< \frac{2}{3}< \frac{11}{15}$

Solution : Given: The numbers are $\frac{2}{3}, \frac{3}{5}, \frac{11}{15}$.
To find the greatest fraction, we have to find the LCM of denominators.
LCM of denominators $=$ LCM $(3, 5, 15) = {(3×5)} = 15$
We have to make all denominators the same for comparison,
$ ⇒\frac{2}{3}\times \frac{5}{5} = \frac{10}{15} $
$ ⇒\frac{3}{5}\times \frac{3}{3} = \frac{9}{15} $
$ ⇒\frac{11}{15}\times \frac{1}{1} = \frac{11}{15} $
Now, by comparing numerators $(9<10<11)$.
So, we can say $\frac{3}{5}< \frac{2}{3}<\frac{11}{15}$.
Hence, the correct answer is $\frac{3}{5}< \frac{2}{3}<\frac{11}{15}$.