with 75k rank in jee mains from general category which Colleges will I get in jossa or csab councelling?

Hi

Your profile suggests that your home state is UP

It's quite difficult to predict because cutoff keeps changing every year depending upon various factors like :-

******number of students that appeared in the  jee main exam,

****** number of available seats,

****** performance of different students in the examination,

****** the category you belong etc.

But yes,

When we go through previous year trend then

>>>>>> With  75k rank

You have low chances for any colleges in josaa, even for GFTIs in josaa you should have got at least around 65k -68k rank.

You have chances in  GFTIs in CSAB  which are listed below along with the link for their previous year cut off  :--

-----) Pondicherry Engineering College, Puducherry( in csab counselling)  :- https://www.careers360.com/colleges/pondicherry-engineering-college-puducherry/cut-off

------) Central University of Rajasthan, Ajmer( in csab counselling)  :- https://www.careers360.com/university/central-university-of-rajasthan-ajmer/cut-off

------) Central Institute of Technology, Kokrajhar( in csab counselling) :- https://www.careers360.com/colleges/central-institute-of-technology-kokrajhar/cut-off

-------) Mizoram University, Aizawl( in csab counselling) :- https://www.careers360.com/university/mizoram-university-aizawl/cut-off

And a few more

This prediction of colleges is  based of past year data but  cut off or closing rank changes every year depending upon many factors like the number of students that give the examination, difficulty level of the JEE main  for different shifts etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Thank you