without calculating square root find the number of digits in square 1089
Hey student,
Number is 1089
No. of digits in 1089, n => 4 (even)
If n is even :
=> then no. of digits in Square Root =n/2
If n is odd :
=> then no. of digits in Square Root =(n+1)/2
In this case n is even
Therefore, No. of digits in Square root of 1089 = n/2 =4/2 = 2
(Square Root of 1089 is 33)
I hope it helps!