Write the product(s) formed when (i) 2-Bromopropane undergoes dehydrohalogenation reaction. (i) Chlorobenzene undergoes nitration reaction. (ii) Methyl bromide is treated with KCN.
Answer (1)
17th May, 2021
Hello candidate,
1. When 2-Bromo Propane undergoes dehydrohalogenation, action involves the removal of halogen and hydrogen group with the addition of a double bond which gives rise to the product as Pentene.
2. When Methyl Bromide reacts with potassium cyanide, then a simple substitution reaction happens which gives the product as methyl cyanide.
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