Question : x, y, and z are 3 values, such that x + y = 12, y + z = 17 and z + x = 19. What is the average of x, y, and z?
Option 1: 10
Option 2: 8
Option 3: 6
Option 4: 4
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 8
Solution : Given: x + y = 12............(equation 1) y + z = 17............(equation 2) z + x = 19............(equation 3) Adding all equations, we get: x + y + y + z + z + x = 12 + 17 + 19 ⇒ 2(x + y + z) = 48 ⇒ x + y + z = 24 Average of x, y, and z = $\frac{\text{Sum of x,y, and z}}{3}$ = $\frac{24}{\text{3}}$ = 8 Hence, the correct answer is 8.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : Simplify the given expression. $\frac{x^3+y^3+z^3-3 x y z}{(x-y)^2+(y-z)^2+(z-x)^2}$
Question : If ${x^2+y^2+z^2=2(x+z-1)}$, then the value of $x^3+y^3+z^3$ is equal to:
Question : If $x(x+y+z)=20$, $y(x+y+z)=30$, and $z(x+y+z)=50$, then the value of $2(x+y+z)$ is:
Question : If $x$ = $y$ = $z$, then $\frac{\left (x+y+z \right )^{2}}{x^{2}+y^{2}+z^{2}}$ is equal to:
Question : If $\small x+y+z=6$ and $xy+yz+zx=10$, then the value of $x^{3}+y^{3}+z^{3}-3xyz$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile