(X+Y) whole square +(Y+Z)whole square +(Z+X)whole square when X+Y+Z=2 and XY +YZ+ ZX= 1
Answer (1)
24th Apr, 2019
Hey Aaditya,
Here’s the solution to the asked problem:-
(X+Y)^2 = X^2 + Y^2 +2XY
(Y+X)^2 = Y^2 + Z^2 + 2YZ
(Z+X)^2 = Z^2 + X^2 +2ZX
(X+Y+Z)^2 = X^2 + Y^2 + Z^2 + 2(XY + YZ + ZX)
Use the above equations to calculate the value. 4th equation could be used for calculation of X^2 + Y^2 + Z^2 and could be substituted in the initial 3 equations for the desired results.
Hope this helps.
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