It is quite simple you first write x in terms of y from first equation and put x in second equation and solve for y . Then , you will get y in terms of a and b , then put y in any of the two equation and get x .
Question : If $a^{2}=by+cz$, $b^{2}=cz+ax$, $c^{2}=ax+by$, then the value of $\frac{x}{a+x}+\frac{y}{b+y}+\frac{z}{c+z}$ is:
Question : The third proportional of the following numbers $(x-y)^2, (x^2-y^2)^2$ is:
Question : If areas of similar triangles $\triangle {ABC}$ and $\triangle {DEF}$ are $ {x}^2 \ \text{cm}^2$ and $ {y}^2 \ \text{cm}^2$, respectively, and EF = a cm, then BC (in cm) is:
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