Answer (1)
Smrity 4th Apr, 2020

Hey,

dy/dx for given equation is equal to

=((e^x+e^-x)d/dx(e^x-e^-x)-(e^x-e^-x)d/dx(e^x+e^-x))/(e^x+e^-x)^2

=((e^x+e^-x)(e-(-e^-x))-(e^x-e^-x)(e^x-e^-x))/(e^x+e^-x)^2

=(((e^x+e^-x)^2)-((e^x-e^-x)^2)/(e^x+e^-x)^2

= 4/(e^x+e^-x)^2

which is the required answer.

I hope this helps.

All the best!


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