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y = e^x + e^-x/ e^x - e^+x find dy/dx
Answer (1)
Hey,
dy/dx for given equation is equal to
=((e^x+e^-x)d/dx(e^x-e^-x)-(e^x-e^-x)d/dx(e^x+e^-x))/(e^x+e^-x)^2
=((e^x+e^-x)(e-(-e^-x))-(e^x-e^-x)(e^x-e^-x))/(e^x+e^-x)^2
=(((e^x+e^-x)^2)-((e^x-e^-x)^2)/(e^x+e^-x)^2
= 4/(e^x+e^-x)^2
which is the required answer.
I hope this helps.
All the best!
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