y = e^x + e^-x/ e^x - e^+x find dy/dx
Also Check: Crack JEE Main 2025 - Join Our Free Crash Course Now!
JEE Main 2025: Sample Papers | Syllabus | Mock Tests | PYQs | Video Lectures
JEE Main 2025: Preparation Guide | High Scoring Topics | Study Plan 100 Days
Hey,
dy/dx for given equation is equal to
=((e^x+e^-x)d/dx(e^x-e^-x)-(e^x-e^-x)d/dx(e^x+e^-x))/(e^x+e^-x)^2
=((e^x+e^-x)(e-(-e^-x))-(e^x-e^-x)(e^x-e^-x))/(e^x+e^-x)^2
=(((e^x+e^-x)^2)-((e^x-e^-x)^2)/(e^x+e^-x)^2
= 4/(e^x+e^-x)^2
which is the required answer.
I hope this helps.
All the best!
Related Questions
x=logt y=dont find my/dx at =pi/2
X+ Y=? Find the value of ?
Integration of e to the power of x^2
Know More about
Joint Entrance Examination (Main)
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates BrochureYour Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.