Y=e^(2logx+3x)
=e^(logx^2).e^3x
=x^2.e^3x

dy/dx = 2x.e^3x+x^2.3.e^3x
=2x.e^3x+3x^2.e^3x

:)

Hey Sidh,



You want to know the differentiation of



Y = e^(2logx + 3x)



Taking log both sides



Log (y) = loge^ (2logx + 3x)



Log (y) =  (2logx + 3x) log e

Log (y) = 2logx + 3x



Differentiating both sides with respect to x



(1 / y) (dy/dx) = 2 / x + 3



dy/dx = (2/x + 3) y



dy/dx = (2/x + 3)(2logx +3x)



Hope it helps :)