Structure of the Atom - Notes, Topics, Formula, Books, FAQs

Structure of the Atom - Notes, Topics, Formula, Books, FAQs

Edited By Team Careers360 | Updated on Oct 22, 2024 04:21 PM IST

The structure of atoms is a very important topic for understanding the physical and chemical properties of various atoms and molecules. Scientists tried to explain the atomic structure from time to time and gave various models of atoms like Dalton's model, Thomson's model, Bohr's model, etc. The electronic configuration of atoms provides insights related to various chemical reactions of elements. The important topics of the structure of atoms class 11 are mentioned below in this article.

Atomic structure is a very basic and fundamental topic to be studied in chemistry and modern physics. Atoms are extremely important particles that makeup all the materials on Earth. Atoms are present in our bodies and they bond together to form molecules, which make up matter. Everything in the universe is composed of individual atoms of various elements that combine together to form molecules. The basic structure of an atom consists of a nucleus containing protons and neutrons and a cloud of electrons revolving around the nucleus.

Without atoms, the world wouldn't have functioned. Atoms make matter, and matter makes everything in the world, with a few exceptions. Below are a few examples of how atoms affect the world:

  • Atoms of oxygen are in the air and keep us alive because oxygen is needed for breathing.
  • Atoms of carbon dioxide are released from our bodies and plants take in the $\mathrm{CO}_2$ so that photosynthesis can take place.
  • Atoms of oxygen and hydrogen bond together to form a molecule of water $\left(\mathrm{H}_2 \mathrm{O}\right)$. Water is so important in the world because it has multiple uses(drinking, cleaning, cooking, transportation). Our survival mostly depends on water.
  • Atoms of Carbon (C) bond together in a particular structure to form Graphite which we use in pencil.

In this chapter, the aspirant will learn some important and basic terms electrons, protons, neutrons, atomic number, mass number, isotopes, isobars, velocity, frequency, wavelength, wavenumber, orbitals, quantum numbers, etc.

Atomic structure subtopics

Atomic structure overview:

atomic_models%20

In this chapter, the candidate will, first of all, know about the atomic theory proposed by Dalton in 1808 who regarded the atom as the indivisible particle of matter. At the end of the nineteenth century, it was proved that atoms are divisible and consist of three fundamental particles: Electrons, protons, and neutrons. Faraday then discovered electrons using a cathode ray discharge tube experiment. Neutrons were discovered by James Chadwick by bombarding a thin sheet of beryllium with $\alpha-$ particles. Various atomic models were proposed to explain the structure of the atom. The aspirant will know about Thomson plum-pudding model, Rutherford's atomic model, and Bohr's model of an atom.

Also Read:

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Line spectrum of hydrogen

When an electric discharge is passed through gaseous hydrogen, the $\mathrm{H}_2$ molecules dissociate and the energetically excited hydrogen atoms produced emit electromagnetic radiation of discrete frequencies. These radiations are emitted because of electronic transitions upon de-excitation to different energy levels and on the basis of the final energy level of transition, the hydrogen spectrum consists of several series of lines named after their discoverers like Lyman series, Balmer Series, Paschen Series, Bracket Series, Pfund Series.

Line Spectrum of Hydrogen-like atoms

$
\frac{1}{\lambda}=R Z^2\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)
$
Where $R$ is called Rydberg constant, $R=109677 \mathrm{~cm}^{-1}, Z$ is atomic number
$n_1=$ final orbit occupied after de-excitation $=1,2,3 \ldots$
$\mathrm{n}_2=$ initial orbit occupied before de-excitation

Lyman Series spectrum:

Transition of electrons from higher orbits to $n=1$ result in the Lyman Series

$
n_1=1 \text { and } n_2=2,3,4 \ldots
$

For H atom, this lies in Ultraviolet region. For elements with higher $Z$, the Balmer lines lie in the Ultraviolet region

Balmer Series Spectrum:

Transition of electrons from higher orbits to $n=2$ result in the Balmer Series

Where $n_1=2$ and $n_2=3,4,5,6 \ldots$
For H atom, this generally lies in visible region.

Paschen, Bracket and Pfund Series spectrums:

Transition of electrons from higher orbits to $n=3,4$ and 5 respectively result in the Paschen, Bracket and the Pfund Series

These lines lie in the Infrared Region for H atom.

spectrums%201

The aspirant will also learn about Planck's quantum theory in which substance absorb or radiate energy discontinuously in the form of small packets. The phenomenon of the photoelectric effect in which there is the ejection of an electron from the surface of a metal when the light of suitable frequency strikes on its surface is something very interesting to know in this chapter. Following it an aspirant will come across four quantum numbers like the principal quantum number, azimuthal quantum number, magnetic quantum number and spin quantum number including the shape and size of different orbitals.

The shape of s orbital: (spherical)

Structure of s- orbital

The shape of p orbital:(dumbbell shaped)

picture2shape%20(1)

The shape of the d orbital:

picture3shape%20(1)

Rules for filling of electrons in various orbitals is a very important part to be studied in this chapter which will be helpful in the rest of the chemistry portion especially in inorganic and organic chemistry.

Rules For Filling Orbitals:

Rule 1 - Aufbau's principle - Lowest energy orbitals are filled first. Thus, the order of filling $1 \mathrm{~s}, 2 \mathrm{~s}, 2 \mathrm{p}, 3 \mathrm{~s}, 3 \mathrm{p}, 4 \mathrm{~s}, 3 \mathrm{~d}$, etc.

Rule 2 - Pauli Exclusion Principle - Only two electrons are permitted per orbital and they must be of opposite spin.

Rule 3- Hund's Rule - No pairing of electron starts in any of the degenerate orbitals until all orbitals of the subshell contain one electron each with parallel spin.

shape

Quantum numbers:

They are the set of four numbers which explain the state of electron i.e., location, energy, type of orbital, orientation of orbital, etc. in an atom. Various quantum numbers are as follows:
1. Principal quantum number( $n$)
2. Azimuthal quantum number($l$)
3. Magnetic quantum number( $m$ )
4. Spin quantum number($s$)

Atomic structure formula:

1. The velocity of the electron in nth Bohr orbit:

$v=2.18 \times 10^8 \frac{Z}{n} \mathrm{~cm} / \mathrm{sec}$

2. The radius of nth Bohr orbital:

$r_n=0.529 \frac{n^2}{z} A^0$

3. The total energy of an electron in nth orbit:

$E_n=-13.6 \frac{z^2}{n^2} \mathrm{eV}$

4. The kinetic energy of electron: -(total energy of electron):

$13.6 \frac{Z^2}{n^2} \mathrm{eV}=-\mathrm{P} \cdot \mathrm{E} / 2$

5.The potential energy of the electron:

$-27.2 \frac{Z^2}{n^2} \mathrm{eV}$

6. Line Spectrum of Hydrogen-like atoms
$
\frac{1}{\lambda}=R Z^2\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)
$

Where R is called Rydberg constant, $R=1.097 * 10^7$ where $\mathrm{Z}=$ atomic number.

7. De-Broglie wavelength

$\lambda=\frac{h}{m v}=\frac{h}{p}$

How to prepare the atomic structure:

The first and foremost thing a candidate should do is to read the NCERT book and be thorough with all the topics covered in this chapter. In order to get away with the confusion of "How to prepare for atomic structure" the aspirant can also take the help of animation and videos which are easily available on the internet, to understand the shape of orbitals, photoelectric effect, Bohr's model and other related topics. It is very important to have a clear picture of the experimental setup and observations in the mind of the candidate. The candidate should also focus on the previous year's question papers related to atomic structure. Based on analysis, it is found that most of the numerical problems are from Bohr's theory and the hydrogen spectrum. These are important topics from exam point of view. So, the candidate should try to solve as many problems from these two topics.

Books for Atomic structure:

To prepare for atomic structure, these are some reference books that should be consulted;

1. J.DLee

2. O.P.Tandon

Some Solved Examples

Example 1: When an electron jumps from $n=4$ to $n=2$ then the change in angular momentum is approximately.
1) $1.1 \times 10^{-34} \mathrm{Js}$
2) (correct) $2.2 \times 10^{-34} \mathrm{Js}$
3) $3.3 \times 10^{-34} \mathrm{Js}$
4) $4.1 \times 10^{-34} \mathrm{Js}$

Solution

The angular momentum of the electron in any $\mathrm{n}^{\text {th }}$ Bohr Orbit is given by

$
\begin{aligned}
& m v r=\frac{n h}{2 \pi} \\
& \Delta L=4\left(\frac{h}{2 \pi}\right)-2\left(\frac{h}{2 \pi}\right)=\frac{h}{\pi} \\
& \Delta L=\frac{6.626 \times 10^{-34}}{3.14}=2.2 \times 10^{-34}
\end{aligned}
$

Hence, the answer is the option (2).

Example 2: Which of the following statements is incorrect for Bohr's model of an atom?

1) (correct) It is valid for a multi-electronic species

2) Angular momentum of an electron is quantized

3) The centripetal force of attraction required for circular motion is provided by the electrostatic force of attraction between the electron and the nucleus

4) Orbits have fixed energy and are referred to as stationary states

Solution

Bohr's model is valid for only electronic species.

All other given statements given in the options are correct.

Hence, the answer is the option (1).

Example 3: The de-Broglie wavelength of a particle of mass 6.63 g moving with a velocity of $100 \mathrm{~ms}^{-1}$ is:
1) (correct) $10^{-33} \mathrm{~m}$
2) $10^{-35} \mathrm{~m}$
3) $10^{-31} \mathrm{~m}$
4) $10^{-25} \mathrm{~m}$

Solution

As discussed in concept:
De-Broglie wavelength:

$
\begin{aligned}
& \lambda=\frac{h}{m v}=\frac{h}{p} \\
& \text { - wherein }
\end{aligned}
$

where $m$ is the mass of the particle
V: its velocity
p: its momentum
So,

$
\begin{aligned}
& \lambda=\frac{6.625 \times 10^{-34}}{6.63 \times 10^{-3} \times 100} \\
& \lambda=10^{-33} \mathrm{~m}
\end{aligned}
$

Hence, the answer is the option (1).

Example 4: The electronic configuration of copper is:

1) (correct) $[\operatorname{Ar}] 3 d^{10} 4 s^1$
2) $[\operatorname{Ar}] 3 d^9 4 s^2$
3) $[\operatorname{Ar}] 3 d^{10} 4 s^2$
4) $[\operatorname{Ar}] 3 d^8 4 s^2$

Solution
Ideally, the electronic configuration of Cu must be [Ar] $3 d^9 4 s^2$ but in this case, the electrons in d-orbitals are not symmetrically filled. Thus to maintain the symmetricity, one electron from the 4 s -orbital goes to the d-orbital and thus Cu maintains the electronic configuration as $[A r] 3 d^{10} 4 s^1$.

Hence, the answer is the option (1).

Conclusion

The presently accepted model for the structure of atoms is a natural outcome of earlier models, as over time scientists tried to overcome various shortcomings faced by earlier models. There is still a huge scope of research in this field as various particles like Quarks, Leptons, etc are discovered by researchers. These subatomic particles have many real-life applications. The revolutionary idea of Quantum Computer is also associated with these particles only.

Frequently Asked Questions (FAQs)

1. What are atoms made of?

Atoms are made of Protons, Neutrons and Electrons.

2. How many electrons are in an atom?

In a neutral atom, the number of electrons are equal to number of protons.

3. Which is heavier, proton or electron?

Proton is almost 1850 times heavier than electron.

4. Who discovered the structure of an atom?

The structure of atom was discovered inititally by John Dalton.

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