The argument is related to the angle which is formed by complex numbers at the origin in the argand plane. There can be multiple arguments that exist for a single complex number but the principle argument is the only one. The applications of the arguments of complex numbers are in the phasor analysis, stability analysis of the control systems, signal processing, and analysis of wave function.
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In this article, we will cover the concept of arguments of a complex number. This concept falls under the broader category of complex numbers. It is not only essential for board exams but also for competitive exams like the Joint Entrance Examination (JEE Main), and other entrance exams such as SRMJEE, BITSAT, WBJEE, BCECE, and more. Over the last ten years of the JEE Main exam (from 2013 to 2023), a total of six questions have been asked on this concept, including one in 2013, one in 2019, one in 2020, one in 2022, and two in 2023.
The number which has no real meaning then these numbers are represented in complex forms. The general form of complex numbers are $a+i b$ where i is iota or$\sqrt{-1}$.
For example,$z=5+2$ is a complex number.
5 here is called the real part and is denoted by Re(z), and 2 is called the imaginary part and is denoted by Im(z)
The argument of a complex number is the angle made by the line representation of the complex number, with the positive x-axis of the argand plane. Any complex number can be represented in the argand plane with the real part marked along the x-axis and the imaginary part marked along the y-axis. The complex number$Z=x+i y$ can be represented as a point $P(x, y)$in the argand plane, and the angle made by the line OP with the positive x-ais is the argument of the complex number.
If a complex number $z=x+i y$ is represented by a point $P$ in the Argand plane and $O P$ forms some angle with a positive x-axis, let's denote it with $\theta$, then $\theta$ is called the argument of z.
$\begin{aligned} & \tan \theta=\frac{\mathrm{PM}}{\mathrm{OM}} \\ & \tan \theta=\frac{\mathrm{y}}{\mathrm{x}}=\frac{\operatorname{Im}(\mathrm{z})}{\operatorname{Re}(\mathrm{z})} \Rightarrow \theta=\tan ^{-1} \frac{\mathrm{y}}{\mathrm{x}} \\ & \arg (\mathrm{z})=\theta=\tan ^{-1} \frac{\mathrm{y}}{\mathrm{x}}\end{aligned}$
If $\theta$ lies between $-\pi<\theta \leq \pi$, then $\theta$ is called a principal argument. The value of the argument differs depending on which quadrant point $(x, y)$ lies.
If it lies in $1^{\text {st }}$ quadrant then it is $\theta$ (acute angle)
If the point lies in 2nd quadrant, then $\arg (z)=\theta=\pi-\tan ^{-1} \frac{y}{|x|}$
So it will be an obtuse +ve angle
If the point lies in lies in 3rd quadrant then $\arg (z)=\theta=-\pi+\tan ^{-1} \frac{y}{z}$
It will be an obtuse -ve angle
If the point lies in 4th quadrant then $\arg (z)=\theta=-\tan ^{-1} \frac{|y|}{x}$
It will be -ve acute angle
Note:
If $\arg (\mathrm{z})=\frac{\pi}{2}$ or $-\frac{\pi}{2}, \mathrm{z}$ is purely imaginary.
If $\arg (\mathrm{z})=0$ or $\pi, \mathrm{z}$ is purely real.
i) $\arg \left(\mathrm{z}_1 \mathrm{z}_2\right)=\arg \left(\mathrm{z}_1\right)+\arg \left(\mathrm{z}_2\right)+2 \mathrm{k} \pi, \mathrm{k}$ is an integer
This formula for argument can be generalized for n number of complexes in a similar way
ii) $\arg \left(\frac{\mathrm{z}_1}{\mathrm{z}_2}\right)=\arg \left(\mathrm{z}_1\right)-\arg \left(\mathrm{z}_2\right)+2 \mathrm{k} \pi$ where k is an integer
$
\text { iii) } \arg (\bar{z})=-\arg (z)
$
iv) $\arg \left(\mathrm{z}^{\mathrm{n}}\right)=\mathrm{n} \cdot \arg (\mathrm{z})+2 \mathrm{k} \pi$ k belongs to an integer
(v) $\left|z_1+z_2\right|=\left|z_1\right|+\left|z_2\right| \Rightarrow \arg \left(z_1\right)=\arg \left(z_2\right)$
(vi) $\left|\mathrm{z}_1+\mathrm{z}_2\right|=|| \mathrm{z}_1|-| \mathrm{z}_2|| \Rightarrow \arg \left(\mathrm{z}_1\right)-\arg \left(\mathrm{z}_2\right)=\pi$
Example 1: Arg $\left(\frac{2 i}{\sqrt{3}-i}\right)$ equals:
Solution:
As we learned in
Definition of Argument/Amplitude of z in Complex Numbers -
$\theta=\tan ^{-1}\left|\frac{y}{x}\right|, z \neq 0$
$\theta, \pi-\theta,-\pi+\theta,-\theta$ are Principal Arguments if z lies in the first, second, third, or fourth quadrant respectively.
Now,
$\begin{aligned} & \frac{2 i}{\sqrt{3}-i}=\frac{2 i}{\sqrt{3}-i} \times \frac{\sqrt{3}+i}{\sqrt{3}+i}=\frac{2 \sqrt{3} i-2}{4} \\ & \Rightarrow \frac{2 i}{\sqrt{3}-i}=\frac{-1}{2}+\frac{i \sqrt{3}}{2}\end{aligned}$
it lies in 2nd quadrant so
argument= $\pi-\tan ^{-1}\left|\frac{\frac{\sqrt{3}}{2}}{\frac{-1}{2}}\right|=\pi-\frac{\pi}{3}=\frac{2 \pi}{3}$
Hence, the required answer is $\frac{2 \pi}{3}$.
Example 2: Let $z_0$ be a root of the quadratic equation, $x^2+x+1=0$. If $z=3+6 i z_0^{81}-3 i z_0^{93}$ then arg z is equal to :
Solution:
Definition of Argument/Amplitude of z in Complex Numbers -
$\theta=\tan ^{-1}\left|\frac{y}{x}\right|, z \neq 0$
$\theta, \pi-\theta,-\pi+\theta,-\theta$ are Principal Arguments if z lies in the first, second, third, or fourth quadrant respectively.
now,
Cube roots of unity -
$z=(1)^{\frac{1}{3}} \Rightarrow z=\cos \frac{2 k \pi}{3}+i \sin \frac{2 k \pi}{3}$
k=0,1,2 so z gives three roots
$\Rightarrow 1, \frac{-1}{2}+i \frac{\sqrt{3}}{2}(\omega), \frac{-1}{2}-i \frac{\sqrt{3}}{2}\left(\omega^2\right)$
- wherein
$\omega=\frac{-1}{2}+\frac{i \sqrt{3}}{2}, \omega^2=\frac{-1}{2}-\frac{i \sqrt{3}}{2}, \omega^3=1,1+\omega+\omega^2=0$
$1, \omega, \omega^2$ are cube roots of unity.
Quadratic Equation
$x^2+x+1=0$, roots are, $\omega$ and $\omega^2$ where $\omega$ is the cube root of unity.
$
z=3+6 i\left(z_0\right)^{81}-3 i\left(z_0\right)^{90}
$
$z_0=\omega$ and $\omega^2$
$
\begin{aligned}
& z=3+6 i(\omega)^{81}-3 i(\omega)^{93} \\
& z=3+3 i \quad \because \omega^3=1 \\
& \arg (z)=\frac{1}{4}
\end{aligned}
$
Hence, the required answer is $\frac{\pi}{4}$.
Example 3: Which of the following is one of the arguments of $z=-\sqrt{3}-3 i$:
1) $\frac{\pi}{3}$
2) $\frac{-5 \pi}{3}$
3) $\frac{-4 \pi}{3}$
4) $\frac{4 \pi}{3}$
Solution
As we learned in
General Argument of a Complex Number -
$2 n \pi+0$
- wherein
$\theta$ is the principal argument of complex numbers.
z lies in 3rd quadrant
its principal argument $=-\pi+\tan ^{-1}\left|\frac{-3}{-\sqrt{3}}\right|=-\pi+\tan ^{-1} \sqrt{3}=-\pi+\frac{\pi}{3}=\frac{-2 \pi}{3}$
$\therefore 2 n \pi-\frac{2 \pi}{3}$ will be its general argument.
for n=1, we get argument = $\frac{4 \pi}{3}$
Hence, the required answer is the option (4).
Example 4: Let a complex number be $w=1-\sqrt{3} i$. Let the other complex number z be such that $|z w|=1$ and $\arg (z)-\arg (w)=\frac{\pi}{2}$. Then the area of the triangle with the vertices origin, a and w is equal to:
Solution:
$\begin{aligned} & \mathrm{w}=1-\sqrt{3} \cdot i \Rightarrow|\mathrm{w}|=2 \\ & \text { Now, }|\mathrm{z}|=\frac{1}{|\mathrm{w}|} \Rightarrow|\mathrm{z}|=\frac{1}{2} \\ & \text { and } \arg (\mathrm{z})=\frac{\pi}{2}+\arg (\mathrm{w})\end{aligned}$
Area of $\Delta=\frac{1}{2} \times 2 \times \frac{1}{2}=\frac{1}{2}$
Hence, the answer is $\frac{1}{2}$
Example 5: Arg $\left(i^{18}+\frac{1}{i^{25}}\right)$ equals:
Solution:
$i^{18}+\frac{1}{i^{25}}=\left(i^4\right)^4 \cdot i^2+\left(\frac{1}{i^4}\right)^6 \cdot \frac{1}{i}=i^2+\frac{1}{i}=-1-i$
As this lies in the third quadrant, so Arg(z) = $-\pi+\tan ^{-1} \left\lvert\, \frac{y}{x}\right.$
Arg $(-1-i)=-\pi+\tan ^{-1}\left|\frac{-1}{-1}\right|=-\pi+\frac{\pi}{4}=\frac{-3 \pi}{4}$
Hence, the required answer is $\frac{-3 \pi}{4}$.
Summary
The arguments help in finding the position of the complex numbers in the argand plane. It provides extra knowledge about complex numbers and its applications are widely used in the analysis of phasor and control systems. Understanding the concept of the arguments is very essential for working with complex numbers in polar coordinates for various applications in science and engineering.
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Frequently Asked Questions(FAQ)-
1. What are the arguments of complex numbers?
Ans: Arguments of complex numbers mean the angle made by complex numbers with origin in the argand plane.
2. What are the principal arguments of complex numbers?
Ans: Principal arguments of a complex number always lie between -180 degrees to 180 degrees.
3. What are the arguments of the complex number x+iy?
Ans: The argument is $\tan ^{-1} \frac{x}{y}$
4. In which quadrant lies when the argument is acute angle?
Ans: First quadrant.
5. In which quadrant lies when the argument is an obtuse angle?
Ans: Second quadrant
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