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1 mole of N2 and 3 moles of H2 produces NH3 at equilibrium calculate the concentration of NH3 at equilibrium if Kc = 4/27


Jainam shah 22nd Nov, 2018
Answers (2)
Sai 30th Apr, 2020
N2+3H2<->2NH3
Then
N2=1-X
H2=3-3X
NH3=2X
THEN K=4/27
AND
X/1-X^2=1
Vikas gehlot 22nd Nov, 2018

The Reaction can be represented as

N2+3H2=2NH3

Let x mol of N2 Got reacted till equilibrium is reached, then According to stoichiometry, Moles of the component Present at equilibrium.

N2=1-x

H2=3-3x

NH3=2x

Then Equilibrium Constant

K=(2x)^2/27(1-x)^3=4/27

therefore   x/(1-x)^2=1

Now You can calculate the X and hence the corresponding concentration at Equilibrium.

2 Comments
Comments (2)
22nd Nov, 2018
Please tell that how to calculate X value in this
Reply
22nd Nov, 2018
I am not able to solve X value so please show me further
Reply

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