2 moles 0f HI are heated in 5 L vessel at 717K.If value of Kc for the reaction 2HI- H2+ I2 at 717K is .0156.Calculate the moles of H2,I2&2HI
Answer (1)
13th Sep, 2018
hii tanuj
Acoording to your question,first of all write the equation-
H2+I2=2HI
initial moles x + x = 0
at equilibrium 1-x + 1-x= 2x
let me explain now,suppose initial moles are x for both reactant and 0 moles for product.now at equilibrium some moles of reactant must be lost suppose it will become 1-x and product will become x but as there is 2 moles of product so it will become 2x.
as kc is given 0.0156 so now we can write it as
kc=(2x) whole square/(1-x) whole square
0.0156=(2x) whole square/(1-x) whole square
0.12=2x/1-x
x=0.05 so now at equilibrium H2 will be 1-0.05=0.95,I2 will be 1-0.05=0.95 and HI will be 2x=0.1
i hope this information helps you.
thank you
Comments (0)
