4. A steel rod having circular cross section with diameter 5 cm and length 3 m is utilized to hang a block of 100 kg at its free end. Its upper end is fixed with the ceiling. Steel density is 8000kg/m3 . Find the total elongation of the rod, taking into account its own weight. Take E = 210 GPa.

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4. A steel rod having circular cross section with diameter 5 cm and length 3 m is utilized to hang a block of 100 kg at its free end. Its upper end is fixed with the ceiling. Steel density is 8000kg/m3 . Find the total elongation of the rod, taking into account its own weight. Take E = 210 GPa.

rahulattri0190 21st Dec, 2020

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Ayush 30th Dec, 2020

Hello Candidate,

The formula for Young's Modulus of Elasticity for steel is given by: Y= Mass Attached* Length/ Elongation* Area of Cross Section.

Here, the value of Young's Modulus=21000 Pascal, Mass Attached=100 kg, Length=3 metres, Area of Cross Section= 22/7*5*5 cm2= .0019 metres2. So, elongation= 1000*3/ .0019*21000= 75.18 metres.

Hope that this answer helps you.

Thank You.

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