one end of a steel wire of length 0.2 m and radius 2×10^-3m is fixed.if the work done in twisting the free end of the wire is 3.85×10^-2J, calculate the angle through which the wire is twisted.Given rigidity modulus of steel wire=8.075×10^11Nm^2 Ans:1.58degree
Answer (1)
2nd Jan, 2022
Hello, I hope you are doing well
This problem can be solved easily by calculating the angle through the following formula:
Work Done = 1/2 Cθ²
Now, we already know the Work done from the question data,
So to calculate C, use the following formula:
C= πηr 4 /2L
Where r and L are radius and length of steel wire, η is the modulus of rigidity for steel wire, which is also given in the question
After getting the value of C, we can get θ by putting the value of W and C in the equation :
Work Done = 1/2 Cθ²
Hope this helps
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