Question : A and B can do a work together in 18 days. A is three times as efficient as B. In how many days can B alone complete the work?
Option 1: 60 days
Option 2: 72 days
Option 3: 54 days
Option 4: 64 days
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Correct Answer: 72 days
Solution :
Given: A and B can do a work together in 18 days.
A is three times as efficient as B.
Total work = Time × Efficiency
Let the efficiencies of B and A are 1 and 3 respectively.
So, total work = 18 × 4 = 72 units
Time taken by B = $\frac{72}{1}$ = 72 days.
Hence, the correct answer is 72 days.
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