Question : A and B can complete a work together in 48 days. A is 4 times as work-efficient as B. In how many days can B alone complete the work?
Option 1: 220 days
Option 2: 320 days
Option 3: 240 days
Option 4: 120 days
Correct Answer: 240 days
Solution :
Efficiency A : B = 4 : 1
If B does 1 unit of work A will do 4 units of work.
So in a day, they will complete 5 units of work together.
We know that total work done = Number of days × Efficiency
Total work done = (48 days × 5 units/day) = 240 units
So, B can complete the whole work alone in $\frac{240}{1}=240$ days.
Hence, the correct answer is 240 days.
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