Question : A, B, and C are three angles of a triangle. If $A-B=45^{\circ}$ and $B-C=15^{\circ}$ then $\angle A=$?
Option 1: 83°
Option 2: 85°
Option 3: 95°
Option 4: 75°
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Correct Answer: 95°
Solution : Given, $A-B=45^{\circ}$ And $B-C=15^{\circ}$ So, $A=45^{\circ}+B$ And, $C=B-15^{\circ}$ By the angle sum property of a triangle, $A+B+C=180^\circ$ ⇒ $45^{\circ}+B+B+B-15^{\circ}=180^{\circ}$ ⇒ $3B+30^\circ = 180^\circ$ ⇒ $B = 50^\circ$ Now, $A=45^{\circ}+B= 45^{\circ}+50^\circ= 95^\circ$ Hence, the correct answer is $95^\circ$
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Question : $\angle A, \angle B$ and $\angle C$ are three angles of a triangle. If $\angle A- \angle B=15^{\circ}, \angle B - \angle C=30^{\circ}$, then $\angle A, \angle B$ and $\angle C$ are:
Question : In $\triangle A B C, \angle A=66^{\circ}$ and $\angle B=50^{\circ}$. If the bisectors of $\angle B$ and $\angle C$ meet at P, then, $\angle B P C-\angle P C A=$?
Question : In a $\triangle A B C, \angle B+\angle C=110^{\circ}$, then find the measure of $\angle A$.
Question : If the angle of a right-angled triangle is 35°, then find the other angles.
Question : An exterior angle of a triangle is 115° and one of the interior opposite angles is 45°. The other two angles are:
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