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a body mass 0.4 kg is whirled in a horizontal circle of radius 5 m it is performed 120 RPM the force acting on it is


gunjalrohini23 24th Oct, 2021
Answer (1)
Rohith Miryala 24th Oct, 2021

Hello Rohini,

w= 120*2*pie / 60 =4*pie rad/sec

radius=5 m ,  mass=0.1 kg

centripetal force=m*v^2/ r

=m*w^2*r

=32(pie)^2  newton

=315.8 N

This is the answer of the question you have asked.

Hope this helps..

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